CBSE Class 8 — Notes, Chapters & Practice Quizzes
Every Class 8 chapter, made friendly — notes with pictures, key words, and a quiz for each chapter.
10 questions · instant score · weak-chapter diagnosis

Students preparing for CBSE Class 8 Annual Assessment
View allChapter 2: The Baudhayana-Pythagoras TheoremClass 8 Mathematics — summary, notes, extra questions & MCQ quiz
Summary
Rooted in Baudhayana’s Sulba-Sutra (c. 800 BCE), this chapter builds to the theorem on right triangles. It starts by doubling a square: the square on a diagonal has twice the area of the original, so an isosceles right triangle with legs \(1\) has hypotenuse \(\sqrt{2}\), and in general \(c^2 = 2a^2\). The number \(\sqrt{2} \approx 1.41421356\ldots\) is shown to be neither a terminating decimal nor a fraction \(\dfrac{m}{n}\) — an early proof of irrationality. Combining two different squares leads to the central result: for a right triangle with legs \(a, b\) and hypotenuse \(c\), \(a^2 + b^2 = c^2\). Baudhayana was the first to state this in general form, centuries before Pythagoras. Integer solutions like \((3, 4, 5)\) and \((5, 12, 13)\) are called Baudhayana (Pythagorean) triples; scaling any triple by \(k\) gives another, so infinitely many exist, and primitive triples have no common factor. The chapter touches Fermat’s Last Theorem and applies the theorem to diagonals, rhombuses and a classic lake-and-lotus problem.
Key terms
Extra questions & answers
Explore interactively
Keyboard: ← → to move · Space to flip
Practice quiz · The Baudhayana-Pythagoras Theorem
Score on this chapter, climb the leaderboard, and get an AI diagnosis of your mistakes.
Dual AI-verified questions Real exam pattern 1 free quiz, then ₹9 per quiz — or all at once for up to 30% less
The Baudhayana-Pythagoras Theorem
Start hereInstant score, answer review and weak-topic diagnosis


