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View allChapter 4: Describing Motion Around UsClass 9 Science — summary, notes, extra questions & NCERT solutions
Summary
This chapter develops a precise way to describe motion in a straight line and in a circle. Position is given relative to a chosen reference point. Distance is the total path length covered (a scalar, only magnitude), while displacement is the shortest straight-line change in position from start to finish (a vector, having both magnitude and direction); displacement can be zero even when distance is not. Speed is \(\text{speed} = \dfrac{\text{distance}}{\text{time}}\) and is a scalar, whereas velocity is displacement per unit time and is a vector. For changing motion we use average speed and average velocity. Acceleration is the rate of change of velocity, \(a = \dfrac{v - u}{t}\), measured in \(\text{m s}^{-2}\); it is positive when speeding up and negative (retardation) when slowing down. For uniform acceleration the three equations of motion apply: \(v = u + at\), \(s = ut + \tfrac{1}{2}at^2\) and \(v^2 = u^2 + 2as\). Motion can be shown with distance-time graphs (slope gives speed) and velocity-time graphs (slope gives acceleration, and the area under the line gives distance). Finally, in uniform circular motion an object moves around a circle at constant speed, yet because its direction keeps changing its velocity is continuously changing, so it is accelerating; examples include a stone whirled on a string or the Moon orbiting the Earth.
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Think It Over
Activity 4.1: Let us analyse
Pause and Ponder
Activity 4.2: Let us calculate
Activity 4.5: Let us investigate
Revise, Reflect, Refine
The Journey Beyond
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