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YOUR STUDY SPACE · CBSE

Describing Motion Around Us — Class 9 Science

Exploration · Chapter 4

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Chapter summary

This chapter develops a precise way to describe motion in a straight line and in a circle. Position is given relative to a chosen reference point. Distance is the total path length covered (a scalar, only magnitude), while displacement is the shortest straight-line change in position from start to finish (a vector, having both magnitude and direction); displacement can be zero even when distance is not. Speed is and is a scalar, whereas velocity is displacement per unit time and is a vector. For changing motion we use average speed and average velocity. Acceleration is the rate of change of velocity, , measured in ; it is positive when speeding up and negative (retardation) when slowing down. For uniform acceleration the three equations of motion apply: , and . Motion can be shown with distance-time graphs (slope gives speed) and velocity-time graphs (slope gives acceleration, and the area under the line gives distance). Finally, in uniform circular motion an object moves around a circle at constant speed, yet because its direction keeps changing its velocity is continuously changing, so it is accelerating; examples include a stone whirled on a string or the Moon orbiting the Earth.
Reference point and positionDistance, displacement and scalars vs vectorsSpeed, velocity and accelerationEquations of motion and motion graphsUniform circular motion

Key ideas & terms

Distance
The total length of the path actually covered by a moving object; a scalar with magnitude only.
Displacement
The shortest straight-line change in position, from initial to final point; a vector with magnitude and direction.
Velocity
The displacement of an object per unit time; a vector that tells both how fast and in which direction it moves.
Acceleration
The rate of change of velocity with time, , measured in .
Equations of motion
For uniform acceleration: , , and .
Uniform circular motion
Motion along a circle at constant speed; the velocity keeps changing direction, so the motion is accelerated.

Extra questions & answers

Differentiate distance and displacement.

Distance is the whole path length covered and is a scalar; displacement is the shortest straight-line gap between start and end positions and is a vector, so it can be zero even when distance is large (e.g. returning to the starting point).

How are speed and velocity different?

Speed is and is a scalar; velocity is displacement per unit time and is a vector, so it also specifies direction and can change even if speed stays the same.

Define acceleration and give its SI unit.

Acceleration is the rate of change of velocity with time, ; its SI unit is metre per second squared, .

What does negative acceleration mean?

It means the velocity is decreasing with time, i.e. the object is slowing down; this is also called retardation or deceleration.

Write the three equations of motion for uniform acceleration.

They are , and , where u is initial velocity, v is final velocity, a is acceleration, s is displacement and t is time.

What does the slope of a distance-time graph represent?

It represents the speed of the object; a steeper slope means a higher speed and a horizontal line means the object is at rest.

What information do you get from a velocity-time graph?

The slope gives the acceleration, and the area enclosed between the line and the time axis gives the distance travelled by the object.

A car starts from rest and reaches in 5 s. Find its acceleration.

Using , so the car accelerates at .

Why is uniform circular motion said to be accelerated even at constant speed?

Because the direction of motion changes continuously around the circle, the velocity (a vector) changes continuously, and any change in velocity means acceleration, even though the speed is constant.

Give two everyday examples of uniform circular motion.

A stone tied to a string and whirled steadily in a circle, and the Moon revolving around the Earth, are both examples of uniform circular motion.

Think It Over

How much distance should we maintain from the truck ahead to avoid a collision if it suddenly applies the brakes?

The safe distance is the total stopping distance, which is the distance covered during the driver's reaction time plus the braking distance. If the truck brakes suddenly, our vehicle continues to move for the reaction time and then decelerates. So , where is our speed and is the magnitude of braking deceleration. It must be larger than the truck's own stopping distance.

Does this distance depend upon the speed with which we are moving?

Yes. Both the reaction distance and the braking distance increase with speed . Doubling the speed more than doubles the required safe distance because braking distance grows as . Therefore at higher speed a much larger gap must be kept.

Activity 4.1: Let us analyse

1. As shown in Fig. 4.5, a ball is thrown vertically upwards from O. It moves up straight till B and then falls back to O. Can this be considered a motion in a straight line?

Yes. Although the ball goes up and then comes down, its trajectory is along the same vertical straight line. The motion is one-dimensional. The use of two separate lines in the figure is only for clarity; displacement and distance are measured along the same line with upward as positive and downward as negative or vice versa.

2. For this motion, fill up the values in Table 4.1. Table 4.1: Distance travelled and displacement of the ball S. No. Position Total distance travelled by the ball from O till that position Displacement of the ball from O till that position 1. O 0 cm 0 cm 2. A 40 cm 40 cm in upward direction 3. B 4. C 5. O

Taking upward as positive and , , , from the figure: 3. B: total distance , displacement upward; 4. C: the ball has gone : total distance , displacement upward; 5. O on return: total distance , displacement . The magnitude of displacement never exceeds total distance and becomes zero on return.

3. Analyse the data filled in Table 4.1 and choose which of the following is true for displacement: (i) It is never zero.

False. As seen in the table, when the ball returns to , total distance is but displacement is . Displacement can be zero even when distance is not zero.

3. Analyse the data filled in Table 4.1 and choose which of the following is true for displacement: (ii) Its magnitude can be greater than the total distance travelled.

False. From the table the magnitude of displacement is while total distance is . The magnitude of displacement is never greater than total distance.

3. Analyse the data filled in Table 4.1 and choose which of the following is true for displacement: (iii) Its magnitude is less than or equal to the total distance travelled.

True. In all cases observed . Equality holds only while moving in one direction without turning back, e.g., . After turning back .

3. Analyse the data filled in Table 4.1 and choose which of the following is true for displacement: (iv) Its magnitude is less than the total distance travelled in all cases.

False. While moving in one direction before turning back, e.g., to and to on the upward journey, and respectively. So it is not less in all cases; it is equal when there is no reversal of direction.

Pause and Ponder

1. In the example of an athlete running back and forth on a straight track (Fig. 4.4), when will the displacement of the athlete be zero? What will be the total distance travelled in that case?

Displacement is the change from the initial position . It becomes zero whenever the athlete returns to the starting point . For example if she goes () and back to , displacement is but total distance is . More generally, any run that ends at gives zero displacement, while total distance is the sum of all segments travelled and is non-zero.

2. Fuel used up in a vehicle depends on which of the following? Justify your answer. (i) Total distance travelled

Fuel consumption depends on total distance travelled. Work done against friction and engine effort is proportional to the actual path length covered, not the net change in position. Even if the vehicle returns to the start and displacement is zero, fuel has been burnt for the whole journey.

2. Fuel used up in a vehicle depends on which of the following? Justify your answer. (ii) Displacement

Displacement alone does not determine fuel use. Two trips can have the same displacement (including zero) but very different path lengths and hence different fuel consumption. Therefore fuel used is not a function of displacement.

3. A ball rolls down an inclined track as shown in Fig. 4.6. Is its motion, a straight line motion? Assuming the starting point of the ball (O) to be the origin, can its motion from O to D be depicted using a horizontal line as shown in Fig. 4.3? Are the values of total distance travelled and magnitude of displacement from O equal or different at positions A, B, C and D?

Yes, the inclined track is straight, so motion is in a straight line, only inclined to the horizontal. It can be represented on a one-dimensional axis along the incline; for convenience we can draw it as a horizontal line with as origin and positions marked by distances along the track. Since the ball never turns back and moves only in one direction down the incline, total distance travelled from equals the magnitude of displacement from at every point: at both are , at , at , at .

4. During a family road trip, you drive 200 km north in three hours. Afterwards, you drive 200 km south in two hours. Find the average speed and average velocity for your entire trip.

Total distance , total time . Average speed . Taking north as positive, displacement . Average velocity . The magnitude of average velocity is zero because you returned to the start.

5. Under what condition(s) is the (i) magnitude of average velocity of an object equal to its average speed?

When the object moves in a straight line in one direction without turning back during the time interval. Then and from and we get .

5. Under what condition(s) is the (ii) magnitude of average velocity of an object zero while its average speed is not zero?

When the object returns to its starting position so that net displacement is zero but path length is non-zero. Then while average speed . Any closed loop or back-and-forth motion, such as the athlete going or the round trip in Q4, gives this condition.

Activity 4.2: Let us calculate

1. The magnitude of average acceleration of cars is generally specified as the time taken by the car to go from 0 km h–1 to 100 km h–1. Look it up on the internet and find this time for various cars, and record those in Table 4.2.

Example entries (actual values vary by model): Small hatchback , Sedan , Sports car . Students should search official specifications and fill the table with the make, model and the quoted to time.

2. Calculate the magnitude of average acceleration for each car. Table 4.2: The magnitude of average acceleration in a time interval Car type Time interval during which the speed goes from 0 to 100 km h–1 Magnitude of average acceleration (m s–2)

. Average acceleration magnitude . Thus for : ; for : ; for : . The smaller the time, the larger the average acceleration.

Activity 4.5: Let us investigate

1. Take a ring, such as an adhesive tape ring and one marble. 2. Place the ring flat on a smooth surface and throw the marble inside the ring in a way that it rotates along the inner boundary of the ring (Fig. 4.24). 3. Predict what will happen if you lift the ring while the marble is moving. 4. Now, after one or two complete revolutions of the marble, pick up the ring without disturbing the motion of the marble. What do you observe? Does the marble continue moving in a circular motion? Or does it move in some other manner? 5. Repeat the activity multiple times to confirm the result.

Prediction: The marble is constrained to a circle by the ring. When the constraint is removed it will continue in the direction it had at that instant. Observation: On lifting the ring the marble leaves the circular path and moves in a straight line tangent to the circle at the point of release, gradually slowing due to friction. Repeated trials show the same tangential straight-line motion, illustrating that the direction of velocity in uniform circular motion is tangential and that without a centripetal constraint the object moves linearly.

Revise, Reflect, Refine

1. My father went to a shop from home which is located at a distance of 250 m on a straight road. On reaching there, he discovered that he forgot to carry a cloth bag. He came home to take it, went to the shop again, bought provisions and came back home. How much was the total distance travelled by him? What was his displacement from home?

Path: Home Shop , Shop Home , Home Shop , Shop Home . Total distance . He ends at home, so change in position from start to end is . Displacement magnitude is zero, direction not defined.

2. A student runs from the ground floor to the fourth floor of a school building to collect a book and then comes down to their classroom on the second floor. If the height of each floor is 3 m, find: (i) the total vertical distance travelled, and

Height of one floor . Ground to fourth floor is up. Fourth to second floor is down. Total distance .

2. A student runs from the ground floor to the fourth floor of a school building to collect a book and then comes down to their classroom on the second floor. If the height of each floor is 3 m, find: (ii) their displacement from the starting point.

Taking upward as positive and ground as , final position is second floor at . Displacement upward. Its magnitude is , much less than total distance .

3. A girl is riding her scooter and finds that its speedometer reading is constant. Is it possible for her scooter to be accelerating and if so, how?

Yes. Speedometer shows magnitude of velocity. Even with constant speed , acceleration can be non-zero if direction changes. In uniform circular motion or while taking a turn, the velocity vector changes direction, so there is acceleration toward the centre of the turn, although speed remains constant.

4. A car starts from rest and its velocity reaches 24 m s–1 in 6 s. Find the average acceleration and the distance travelled in these 6 s.

. Average acceleration in the direction of motion. With constant acceleration, distance or .

5. A motorbike moving with initial velocity 28 m s–1 and constant acceleration stops after travelling 98 m. Find the acceleration of the motorbike and the time taken to come to a stop.

. Using : so . The negative sign shows deceleration opposite to velocity. From : so .

6. Fig. 4.27 shows a position-time graph of two objects A and B that are moving along the parallel tracks in the same direction. Do objects A and B ever have equal velocity? Justify your answer.

Velocity is the slope of the position-time graph. If one graph is a straight line and the other is curved, the slope of the curved graph changes with time. Equal velocity occurs at the instant where the tangent to the curved graph is parallel to the straight line. If the figure shows two straight lines with different slopes, they never have equal velocity; if one is curved, there will be a point where the slopes match. In many textbook versions A is straight and B is curved and they intersect but the slopes are equal only where the tangent to B is parallel to A.

7. A graph in Fig. 4.28 shows the change in position with time for two objects A and B moving in a straight line from 0 to 10 seconds. Choose the correct option(s). (i) The average velocity of both over the 10 s time interval is equal since they have the same initial and final positions.

True. Both start at the same position at and end at the same position at , so displacement is identical. Average velocity is therefore equal for both, even though their detailed motions differ.

7. A graph in Fig. 4.28 shows the change in position with time for two objects A and B moving in a straight line from 0 to 10 seconds. Choose the correct option(s). (ii) The average speeds of both over the 10 s time interval are equal since both cover equal distance in equal time.

False. Average speed depends on total path length, not net displacement. If one object back-tracks, its total distance is larger. The position-time graph for B shows back-and-forth movement, so its total distance is greater than A's monotonic movement.

7. A graph in Fig. 4.28 shows the change in position with time for two objects A and B moving in a straight line from 0 to 10 seconds. Choose the correct option(s). (iii) The average speed of A over the 10 s time interval is lower than that of B since it covers a shorter distance than B in 10 seconds.

True. Object A moves steadily from start to end without reversing, while B goes beyond and returns, covering extra length. Hence distance travelled by B is greater, so average speed of B is greater than that of A.

7. A graph in Fig. 4.28 shows the change in position with time for two objects A and B moving in a straight line from 0 to 10 seconds. Choose the correct option(s). (iv) The average speed of A over the 10 s time interval is greater than that of B since B’s speed is lower than A’s in some segments.

False. Although B may move slowly in some segments, its total path length over the whole is larger, so its overall average speed is higher, not lower, than A's.

8. A truck driver driving at the speed of 54 km h–1 notices a road sign with a speed limit of 40 km h–1 (Fig. 4.29) for trucks. He slows down to 36 km h–1 in 36 s. What was the distance travelled by him during this time? Assume the acceleration to be constant while slowing down.

. Acceleration . Distance with constant acceleration . Alternatively .

9. A car starts from rest and accelerates uniformly to 20 m s–1 in 5 seconds. It then travels at 20 m s–1 for 10 seconds and finally applies the brake (with uniform acceleration) to stop in 6 seconds. Find the total distance travelled.

Phase 1: so , . Phase 2: constant velocity . Phase 3: , . Total .

10. A bus is travelling at 36 km h–1 when the driver sees an obstacle 30 m ahead. The driver takes 0.5 seconds to react before pressing the brake. Once the brake is applied, the velocity of the bus reduces with constant acceleration of 2.5 m s–2. Will the bus be able to stop before reaching the obstacle?

. During reaction time . Braking distance with : gives so . Total stopping distance which is less than . Yes, the bus stops about before the obstacle, assuming dry road and constant deceleration.

11. A student said, “The Earth moves around the Sun”. In this context, discuss whether an object kept on the Earth can be considered to be at rest.

Rest and motion are relative to the reference point. With respect to the Earth's surface, a book on a table does not change position, so it is at rest in the Earth frame. With respect to the Sun or stars, the same book is moving as the Earth orbits at about and rotates daily. So an object can be at rest in one reference frame and in motion in another; there is no absolute rest.

12. The velocity-time graph from 0 s to 120 s for a cyclist is shown in Fig. 4.30. Shade the areas (in different colours) representing the displacement of the cyclist (i) while cyclist is moving with constant velocity.

On a velocity-time graph displacement is the area under the curve. The segment where the graph is horizontal, parallel to the time axis, represents constant velocity. Its area is a rectangle: . That rectangle should be shaded with one colour.

12. The velocity-time graph from 0 s to 120 s for a cyclist is shown in Fig. 4.30. Shade the areas (in different colours) representing the displacement of the cyclist (ii) when the velocity of cyclist is decreasing.

The segment where the graph slopes downward represents decreasing velocity with negative acceleration. Its area, which is a triangle or trapezium under that sloping line, represents displacement during deceleration and should be shaded with a different colour.

12. The velocity-time graph from 0 s to 120 s for a cyclist is shown in Fig. 4.30. Also, calculate the displacement and average acceleration in the 120 s time interval.

The displacement equals the area under the velocity–time graph (Fig. 4.30). Reading the graph, the velocity rises from 0 to 3 m s over 0–20 s (area m), stays near 3 m s from about 20–100 s (area m), then falls from 3 to about 2 m s over 100–120 s (area m). Total displacement m. The average acceleration over the interval is (small and positive).

13. A girl is preparing for her first marathon by running on a straight road. She uses a smartwatch to calculate her running speed at different intervals. The graph (Fig. 4.31) depicts her velocity versus time. Estimate the running distance based on the graph.

The distance is the area under the velocity–time graph (Fig. 4.31), where velocity is in km h and time in hours. The run lasts about 6 hours with velocity peaking near 7.5 km h and averaging roughly 6 km h, so the distance average speed time km — consistent with marathon-distance training.

14. On entering a state highway, a car continues to move with a constant velocity of 6 m s–1 for 2 minutes and then accelerates with a constant acceleration 1 m s–2 for 6 seconds. Find the displacement of the car on the state highway in the 2 min 6 s time interval by drawing a velocity-time graph for its motion.

Draw time on x-axis and velocity on y-axis. For to graph is horizontal at ; for to it rises linearly to . Displacement is area under graph: rectangle plus trapezium for last : . Total in .

15. Two cars A and B start moving with a constant acceleration from rest in a straight line. Car A attains a velocity of 5 m s–1 in 5 s. Car B attains a velocity of 3 m s–1 in 10 s. Plot the velocity-time graphs for both the cars in the same graph. Using the graph, calculate the displacement mentioned in the two time intervals (Hint: Calculate the acceleration in both cases. Then calculate their velocities at five instants of time to plot the graph).

. Plot time on x-axis, velocity on y-axis: both lines through origin, A steeper. For A area under line for to is triangle . For B for to area is . Hence displacement of A in 5 s is and of B in 10 s is .

16. Rohan studies science from 6 PM to 7:30 PM at home. Consider the tip of the minute’s hand of the wall clock. During the given time interval, what is its: (i) distance travelled,

Time interval , which is revolutions. Circumference . Distance .

16. Rohan studies science from 6 PM to 7:30 PM at home. Consider the tip of the minute’s hand of the wall clock. During the given time interval, what is its: (ii) displacement,

At PM the minute hand points at 12, at it points at 6, opposite side of the dial. After one full revolution the tip returns to start, plus a half revolution takes it to the antipodal point. Magnitude of displacement is the diameter , directed from the initial position toward the final position.

16. Rohan studies science from 6 PM to 7:30 PM at home. Consider the tip of the minute’s hand of the wall clock. During the given time interval, what is its: (iii) speed, and

Average speed . Instantaneous speed of the tip is constant .

16. Rohan studies science from 6 PM to 7:30 PM at home. Consider the tip of the minute’s hand of the wall clock. During the given time interval, what is its: (iv) velocity. The length of the minute’s hand is 7 cm (Fig. 4.32).

Average velocity in the direction from the initial tip position at 12 to the final position at 6, i.e., vertically downward on the clock face. Its magnitude is much smaller than average speed because displacement is smaller than path length.

The Journey Beyond

Take a cardboard disc (radius ~ 8 cm) (Fig. 4.33). Write numbers 1 to 12 on the outer part (7 cm from the centre) and the letters ‘ABCDEF’ on the inner part (4 cm from the centre), using the same font size. Spin the disc slowly, then faster and observe how the numbers and letters appear. Why do the numbers fade or disappear while the letters remain visible? Are the speeds of the numbers and letters the same or different? Justify your answer.

When the disc rotates with angular velocity , linear speed is . The outer numbers at move faster than inner letters at : . At higher the outer numbers blur first because their larger speed exceeds the eye's persistence of vision limit, while slower inner letters remain recognizable. Angular speed is same for all points, linear speed increases with radius.

Many smartphones have an inbuilt accelerometer that can detect very small accelerations. Install an app, such as Phyphox (phyphox.org) and open ‘Accelerometer (without g)’. Note the readings when (i) the phone is on an outstretched palm, and (ii) the phone is kept on the floor. What differences do you observe? What does this tell you about motion and acceleration in real situations? (Such tiny, involuntary movements are also studied in medical research, for example, in movement disorders) This activity is recommended to be performed as a classroom group activity facilitated by teacher.

On the palm the accelerometer shows small fluctuating accelerations of order due to hand tremor, heartbeat and muscle micro-movements. On the stable floor the readings are near zero, noise. This shows that even apparently still objects have tiny accelerations and that true zero acceleration is an idealisation; sensitive sensors reveal continuous small motions in living systems.

For motion in a straight line with constant acceleration, we derived two primary equations given by Eq. (4.4a) and (4.4b). Using these two equations, three more equations can be derived, out of which we derived one given in Eq. (4.4c). Derive the remaining two equations given below s = vt - 1/2 at^2 s = 1/2 (u+v)t In mathematics, you have learnt the formula for calculating the area of a trapezium. Using that formula, derive the second equation given above.

From we have . Substitute in : . For the second, area under velocity-time graph is trapezium with parallel sides and and height : . This also follows by eliminating : add gives , multiply by gives .

Plot graphs for data given in Table 4.4, using different X and Y scales, on different graph papers. Compare the graphs to find how the appearance of graph is affected by the choice of scales and decide which scale is better and why. Now repeat this with any graph plotting app. Such apps generally automatically adjust the axes to fit the data well on the screen.

Changing scales stretches or compresses axes: a small scale on the x-axis makes the curve look steeper, a large scale makes it flatter, but the physical slope corrected for scale remains the same. The best scale uses most of the graph paper, is easy to read (e.g., or ), and avoids cramped or overly sparse plots. Apps auto-scale to fill the screen, giving a balanced aspect ratio that is usually optimal for interpretation.

Talk to a motor mechanic about how a vehicle’s braking or stopping distance is affected by: (i) wet roads, (ii) worn-out tyres, (iii) higher vehicle mass, (iv) driving at night, (v) fog, (vi) severe weather (rain, snow, storm), and (vii) driver reaction time. Using this information, design safety posters for your school and prepare a short skit to present it in the assembly.

Key points: wet or icy roads reduce friction so deceleration decreases and braking distance increases; worn tyres have less grip and longer distance; heavier mass requires larger braking force for same ; night, fog and storms reduce visibility, increasing reaction time and thus reaction distance ; distracted or tired drivers also increase . Posters should emphasize maintain safe following distance , reduce speed in adverse conditions, check tyres and brakes, and avoid sudden acceleration. Skit can enact a safe driver keeping gap versus a tailgating driver facing near-collision.