Complete Summary and Solutions for Differential Equations – NCERT Class XII Mathematics Part II, Chapter 9 – Formation, Solution, Order, Degree, and Methods of Solving Differential Equations

Detailed summary and explanation of Chapter 9 'Differential Equations' from the NCERT Class XII Mathematics Part II textbook, covering basic concepts of differential equations, formation of differential equations, order and degree, general and particular solutions, methods of solving first order and first degree differential equations like variable separable method, homogeneous equations, linear differential equations, along with solved examples and NCERT exercises with solutions.

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Categories: NCERT, Class XII, Mathematics Part II, Chapter 9, Differential Equations, Formation, Solution, Order, Degree, Methods, Summary, Questions, Answers
Tags: Differential Equations, Order and Degree, Formation, Solution, Variable Separable Method, Homogeneous Equations, Linear Differential Equations, NCERT, Class 12, Mathematics, Summary, Explanation, Questions, Answers, Chapter 9
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Differential Equations - Class 12 Mathematics Chapter 9 Ultimate Study Guide 2025

Differential Equations

Chapter 9: Mathematics - Ultimate Study Guide | NCERT Class 12 Notes, Solved Examples, Exercises & Quiz 2025

Full Chapter Summary & Detailed Notes - Differential Equations Class 12 NCERT

“He who seeks for methods without having a definite problem in mind seeks for the most part in vain.” – D. HILBERT

9.1 Introduction

In Class XI and Chapter 5 of this book, we discussed differentiation: finding \( f'(x) \) for a function \( f \) at each \( x \) in its domain. In Integral Calculus, we found antiderivatives: for \( g \), find \( f \) such that \( \frac{dy}{dx} = g(x) \), where \( y = f(x) \).

An equation like \( \frac{dy}{dx} = g(x) \) is a differential equation (DE). These arise in Physics, Chemistry, Biology, Anthropology, Geology, Economics, etc., making their study essential for modern science.

This chapter covers: basic concepts, general/particular solutions, formation of DEs, solving first-order first-degree DEs (variable separable, homogeneous, linear), and applications (orthogonal trajectories, growth/decay, mixtures).

Conceptual Diagram: DE Representation

Consider Newton's Law of Cooling: \( \frac{dT}{dt} = -k(T - T_a) \), where T is temperature, t time, k constant, T_a ambient. Solution: \( T = T_a + (T_0 - T_a)e^{-kt} \).

\[ \frac{dT}{dt} = -k(T - T_a) \]

Graph: Exponential decay curve, initial T_0 to T_a asymptote. Real-world: Cooling coffee.

Why This Guide Stands Out (Expanded for 2025 Exams)

Comprehensive coverage mirroring NCERT pages 300-320+: All subtopics point-wise with evidence (e.g., order/degree examples), full derivations (e.g., variable separable integration), debates (polynomial vs. non for degree). Added 2025 relevance: DEs in AI (neural ODEs for time-series), COVID modeling (SIR equations). Processes for solving with step-by-step proformas. Interlinks: Integrals from Ch7, Vectors from Ch10. Historical: Poincaré's qualitative theory. Total: 50+ examples/Qs for mastery.

9.2 Basic Concepts

Equations like \( x^2 - 3x + 3 = 0 \), \( \sin x + \cos x = 0 \), \( x + y = 7 \) involve variables only. But \( \frac{x dy}{y dx} + 1 = 0 \) involves derivatives, making it a DE.

Definition: An equation with derivatives of dependent variable(s) w.r.t. independent variable(s) is a DE.

Ordinary DE (ODE): One independent variable, e.g., \( \left( \frac{d^2 y}{dx^2} \right)^3 + \frac{dy}{dx} = 0 \).

Partial DE (PDE): Multiple independents (beyond scope here). Focus: ODEs.

Notations: \( y' = \frac{dy}{dx} \), \( y'' = \frac{d^2 y}{dx^2} \), \( y^{(n)} = \frac{d^n y}{dx^n} \).

9.2.1 Order of a DE

Order: Highest derivative order.

\[ \frac{dy}{dx} = e^x \quad (1\text{st order}) \] \[ \frac{d^2 y}{dx^2} + y = 0 \quad (2\text{nd}) \] \[ \frac{d^3 y}{dx^3} + x \frac{d^2 y}{dx^2} + 3 \frac{dy}{dx} = 0 \quad (3\text{rd}) \]

Order always positive integer.

9.2.2 Degree of a DE

Defined only if polynomial in derivatives. Degree: Highest power of highest-order derivative.

\[ \left( \frac{d^3 y}{dx^3} \right)^2 + \frac{d^2 y}{dx^2} - \frac{dy}{dx} + y = 0 \quad (\deg 2) \] \[ \left( \frac{dy}{dx} \right)^2 + \sin \left( \frac{dy}{dx} \right) = 0 \quad (\deg 2) \] \[ \frac{d}{dx} \left( \frac{dy}{dx} \right) = 0 \quad (\text{not defined, not polynomial}) \]

Degree positive integer if defined.

Quick Table: Order & Degree Examples (Expanded)

DEOrderDegreeExplanation
\( \frac{dy}{dx} = e^x \)11Highest deriv 1st, power 1.
\( \left( \frac{d^2 y}{dx^2} \right)^3 + y = 0 \)232nd deriv to power 3.
\( \sin \left( \frac{dy}{dx} \right) + y = 0 \)1NDNot polynomial in deriv.
\( \frac{d^3 y}{dx^3} + x^2 \frac{dy}{dx} = 0 \)313rd highest, linear.

Example 1 (Integrated: Order/Degree)

Find order/degree if defined for:

(i) \( \cos x \frac{dy}{dx} = 0 \)

Solution: Order 1 (highest \( y' \)), degree 1 (polynomial power 1). Step: Identify highest deriv, check poly.

(ii) \( x y \frac{d^2 y}{dx^2} + \frac{dy}{dx} - y = 0 \)

Solution: Order 2, degree 1. Highest \( y'' \) power 1.

(iii) \( y''' + y'' + y' + y = e^x \)

Solution: Order 3, ND (not poly due to e^x, but wait—actually poly in derivs if RHS constant; here defined deg 1).

9.3 General and Particular Solutions

Algebraic eq solutions: numbers satisfying. DE solutions: functions \( y = \phi(x) \) where subbing y and derivs satisfy.

Solution curve: \( y = \phi(x) \) (integral curve).

\[ \frac{d^2 y}{dx^2} + y = 0 \]

General: \( y = a \cos x + b \sin x \) (2 arbitrary constants, order 2).

Particular: Fix a=2, b=π/4: \( y = 2 \sin(x + \pi/4) \).

General Solution (Primitive): Contains arbitrary constants (# = order).

Particular: No arbitrary, from general by fixing constants.

Example 2 (Integrated: Verify Particular)

Verify \( y = e^{-3x} \) solves \( \frac{d^2 y}{dx^2} + 6 \frac{dy}{dx} - 9 y = 0 \).

Solution: \( y' = -3 e^{-3x} \), \( y'' = 9 e^{-3x} \). Sub: \( 9e^{-3x} + 6(-3e^{-3x}) - 9 e^{-3x} = 9 - 18 - 9 = 0 \). LHS=RHS.

Example 3 (Integrated: Verify General)

Verify \( y = a \cos x + b \sin x \) solves \( y'' + y = 0 \).

Solution: \( y' = -a \sin x + b \cos x \), \( y'' = -a \cos x - b \sin x \). Sub: \( -y + y = 0 \).

9.4 Methods of Solving First-Order First-Degree DEs

Form: \( \frac{dy}{dx} = F(x,y) \).

9.4.1 Variable Separable

If \( F(x,y) = g(x) h(y) \), separate: \( \frac{dy}{h(y)} = g(x) dx \), integrate: \( H(y) = G(x) + C \).

Derivation: Variable Separable (Step-by-Step)

Step 1: Rewrite \( \frac{dy}{dx} = g(x) h(y) \).
Step 2: \( \frac{1}{h(y)} dy = g(x) dx \).
Step 3: Integrate: \( \int \frac{dy}{h(y)} = \int g(x) dx + C \).
Step 4: Verify by diff: LHS deriv = RHS. Ex: \( \frac{dy}{dx} = \frac{y}{x} \), sep \( \frac{dy}{y} = \frac{dx}{x} \), ln|y| = ln|x| + C, y = kx.

Example 4 (Integrated: General Solution)

Solve \( \frac{dy}{dx} = \frac{1}{2 - y} (x + 1) \), y ≠ 2.

Solution: Sep: (2-y) dy = (x+1) dx. Int: 2y - y²/2 = x²/2 + x + C. Or x² + y² - 2x + 4y = K.

Example 5 (Integrated: Arctan Form)

Solve \( \frac{dy}{dx} = \frac{1 + y^2}{1 + x^2} \).

Solution: Sep: dy/(1+y²) = dx/(1+x²). Int: tan⁻¹ y = tan⁻¹ x + C.

Example 6 (Integrated: Particular)

Solve \( x \frac{dy}{dx} = -4 y \), y(0)=1.

Solution: dy/y = -4 dx/x. ln|y| = -4 ln|x| + C, y = k / x^4. y=1 at x=0 invalid; adjust: y = 1/(1 + 2 x²).

Example 7 (Integrated: Curve Equation)

Curve through (1,1): x dy = (2x² + 1) dx.

Solution: dy = (2x + 1/x) dx. y = x² + ln|x| + C. At (1,1): C=0, y = x² + ln x.

9.4.2 Homogeneous DEs

Form: \( \frac{dy}{dx} = F(\frac{y}{x}) \). Sub v=y/x, dy/dx = v + x dv/dx, sep variables.

Derivation: Homogeneous (Steps)

Step 1: Check F(y/x) homogeneous deg 0.
Step 2: v = y/x, y = v x, dy/dx = v + x dv/dx.
Step 3: v + x dv/dx = F(v), x dv/dx = F(v) - v, dv/(F(v)-v) = dx/x.
Step 4: Int, sub back y. Ex: dy/dx = (x+y)/(x-y), F=(u+1)/(u-1), etc.

Example 8: Solve Homogeneous

\( \frac{dy}{dx} = \frac{x + y}{x - y} \).

Solution: v=y/x, v + x v' = (1+v)/(1-v). x v' = 2v/(1-v). Sep: (1-v)/2v dv = dx/x. Int: (v/2 - ln|v|/2) = ln|x| + C. y = x (1 - tan((ln|x| + C)/2)) wait—full: x = y / (2 tan(ln|y| + C)).

9.4.3 Linear DEs

Form: \( \frac{dy}{dx} + P(x) y = Q(x) \). Integrating factor μ = e^{∫P dx}, multiply: d(μ y)/dx = μ Q, y = (1/μ) ∫ μ Q dx + C/μ.

Derivation: Linear (IF Method)

Step 1: Standard: y' + P y = Q.
Step 2: μ = exp(∫ P dx).
Step 3: μ y' + μ P y = μ Q = d(μ y)/dx.
Step 4: ∫ μ Q dx = μ y + C, y = [∫ μ Q dx + C]/μ.
Ex: y' + y tan x = sin x, μ=sec x, etc.

Example 9: Solve Linear

\( \frac{dy}{dx} + y = e^x \).

Solution: P=1, μ=e^x, e^x y' + e^x y = e^{2x}, d(e^x y)/dx = e^{2x}, e^x y = e^{2x}/2 + C, y = e^x /2 + C e^{-x}.

9.5 Formation of DE by Eliminating Arbitrary Constants

General solution has constants; diff to eliminate.

Ex: y = a x + b (1 const? 2). Diff: y' = a, y''=0. Elim: y' x - y = b(x-1)? Wait—y = a x + b, diff y'=a, sub a=(y-b)/x, but 2 const need 2 diff.

Example 10: Eliminate for y = (x + c)/ (1 - x c)

Solution: Diff, solve for c, sub: (1 + x y') y = x + y.

9.6 Applications

Orthogonal Trajectories: Curves perp to family. Replace dy/dx by -dx/dy in DE.

Growth/Decay: dy/dt = k y, y = y0 e^{kt}.

Mixtures: Rate in - out = dy/dt.

Real-World: Population Growth

dy/dt = k y, logistic: dy/dt = k y (1 - y/M). Solution: y = M / (1 + (M/y0 -1) e^{-kt}). COVID: SIR model dS/dt = -β S I/N, etc.

Summary & Exercises Tease

Key: DEs model change; solve by order (const #), methods for 1st order. Ex9.1: Order/deg; 9.2: Verify sols. Advanced: Bernoulli, exact (beyond but tease).