Complete Summary and Solutions for Atoms – NCERT Class XII Physics Part II, Chapter 12 – Atomic Models, Nuclear Structure, and Atomic Properties
Detailed summary and explanation of Chapter 12 'Atoms' from the NCERT Class XII Physics Part II textbook, covering atomic models, structure of the nucleus, isotopes, isobars, and atomic properties, along with solved NCERT questions and answers.
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Categories: NCERT, Class XII, Physics Part II, Chapter 12, Atoms, Atomic Models, Nuclear Structure, Isotopes, Isobars, Summary, Questions, Answers
Uniform +ve sphere with e- like plums; vs actual nuclear.
12.2 Alpha-Particle Scattering & Rutherford’s Nuclear Model
Summary in Points: Geiger-Marsden 1911: Alpha beam on gold foil; most pass undeflected (0.14% >1° scatter, 1/8000 >90°). Rutherford: Large deflections imply concentrated +ve mass (nucleus). Size: Nucleus 10^{-15}-10^{-14}m; atom 10^{-10}m (empty space). Trajectory: Coulomb repulsion; impact parameter b small → large θ. Head-on: Rebounds.
Summary in Points: Emission: Bright lines (excited gas); absorption: Dark lines (continuous through gas). H spectrum: Balmer series (visible). Fingerprint for elements.
Expanded: Evidence: Fig 12.5 H lines; debates: Continuous vs discrete; real: Spectroscopy ID.
12.4 Bohr Model of Hydrogen Atom
Summary in Points: Fixes Rutherford: Postulates - Stable orbits (no radiation), L=nh/2π, transitions emit hν=E_i-E_f. Radius r_n = n² h² ε_0 / (π m e²); E_n = -13.6 / n² eV. Ground n=1: -13.6 eV (ionization 13.6 eV).
Energy Levels: n=1 lowest; excited higher, closer spacing.
Expanded: Evidence: Matches ionization; debates: Semiclassical; real: H lamp spectra.
Diagram: Energy Levels
Horizontal lines n=1 to ∞; ionization at 0 eV.
12.5 Line Spectra of Hydrogen
Summary in Points: Transitions: hν = E_i - E_f; series (Lyman UV, Balmer visible, Paschen IR). Explains discrete lines.
All terms from chapter; detailed with examples, relevance. Expanded: 30+ terms grouped by subtopic; added advanced like "stationary state", "principal quantum number".
Plum Pudding Model
Thomson: Uniform +ve with embedded e-. Ex: Watermelon seeds. Relevance: Early uniform idea, failed scattering.
Energy to remove e- (13.6 eV H). Ex: Ground state. Relevance: Binding measure.
Emission Line Spectrum
Bright lines on dark. Ex: H Balmer. Relevance: Atomic fingerprint.
Absorption Spectrum
Dark lines in continuous. Ex: Solar Fraunhofer. Relevance: Gas absorption.
de Broglie Wavelength
λ=h/p for particles. Ex: Electron waves. Relevance: Standing orbits.
Hydrogenic Atom
One e-, +Ze nucleus. Ex: He+. Relevance: Bohr applies.
Tip: Group by model (Thomson/Rutherford/Bohr); examples for recall. Depth: Debates (e.g., stability). Errors: Confuse n and l. Interlinks: To waves Ch11. Advanced: Balmer formula. Real-Life: LEDs. Graphs: E vs n. Coherent: Evidence → Interpretation. For easy learning: Flashcard per term with example.
Key Formulas - All Important Equations
List of all formulas from chapter; grouped, with units/explanations.
Formula
Description
Units/Example
F = (1/(4πε₀)) (2e)(Ze)/r²
Coulomb repulsion alpha-gold
N; r in m
d = (1/(4πε₀)) (2Ze²)/K
Closest approach
m; K kinetic energy
Fe = Fc: (1/(4πε₀)) e²/r² = m v² / r
Centripetal balance
For orbits
L = n h / 2π
Angular momentum quantization
J s; n integer
r_n = n² h² ε₀ / (π m e²)
Bohr radius
m; a₀=0.53 Å for n=1
E_n = - (m e⁴) / (8 ε₀² h² n²) = -13.6 / n² eV
Energy levels
eV
h ν = E_i - E_f
Photon emission
J; transitions
2π r_n = n λ
de Broglie standing wave
λ = h / (m v)
Tip: Memorize with derivations; practice n=1 values.
Derivations - Detailed Guide
Key derivations with steps; from PDF (e.g., Bohr radius, energy).
All solved examples from the PDF with detailed explanations.
Example 12.1: In Rutherford’s nuclear model, nucleus ~10^{-15}m, electron orbit ~10^{-10}m. If solar system scaled to atom proportions, Earth orbit vs actual? (Earth r=1.5×10^{11}m, Sun r=7×10^8 m)
Simple Explanation: Compare emptiness.
Solution: Ratio r_e / r_n = 10^5. Scaled Earth r = 10^5 × 7×10^8 = 7×10^{13} m (>100× actual). Atom emptier than solar system.
Simple Way: Vast empty space.
Example 12.2: Distance closest approach 7.7 MeV alpha to Au nucleus?
Simple Explanation: Energy conservation to stop.
Solution: K = U at d: d = (1/4πε₀) (2 Z e²) / K. Z=79, K=1.23×10^{-12}J → d=3×10^{-14}m=30 fm. Actual nucleus smaller; no touch.
Simple Way: Potential equals kinetic.
Example 12.3: Orbital r, v for H ground state? Ionization 13.6 eV.
Simple Explanation: From E_n.
Solution: E=-13.6 eV=-2.2×10^{-18}J. r = [n² h² ε₀ / (π m e²)] n=1 → 5.3×10^{-11}m. v = e² / (2 ε₀ h) → 2.2×10^6 m/s.
Simple Way: Quantized formulas.
Example 12.4: Classical frequency revolving e- in H? r=5.3×10^{-11}m, v=2.2×10^6 m/s.
Simple Explanation: Orbital ν.
Solution: ν = v / (2π r) = 6.6×10^{15} Hz. Emitted light same classically (wrong).
Simple Way: Revolution rate.
Tip: All textbook examples covered with full details from PDF.
NCERT Textbook Exercise Questions & Solutions
All NCERT exercise questions with detailed solutions (12.1 to 12.9).
12.1 Choose correct: (a) Atom size Thomson vs Rutherford? (b) Ground state equilibrium? (c) Classical collapse? (d) Mass distribution? (e) +ve mass in?
Solution:
(a) No different. (b) Thomson stable, Rutherford net force. (c) Rutherford. (d) Thomson continuous, Rutherford non-uniform. (e) Rutherford.
Long Note: Model contrasts.
12.2 Alpha scattering on solid H foil? Expect?
Solution:
H Z=1 small repulsion; less scatter, more transmission than Au.
Long Note: Light nucleus recoils.
12.3 ΔE=2.3 eV transition frequency?
Solution:
ν = ΔE / h = 2.3×1.6×10^{-19} / (6.6×10^{-34}) ≈ 5.6×10^{14} Hz.